Question

a bucket is in the form of a frustum of a cone whose radii of bottom in top I 7 cm and 28 CM respectively if the capacity of the bucket is 21560 cm cube find the whole surface area of the bucket​

Answer 1

Answer:


Step-by-step explanation:

Radius of upper part of the bucket(R) = 28 cm


Radius of Lower part of the bucket(r)= 7 cm


Volume of the bucket = 1/3πh( R²+r²+Rr)


21560 = 1/3×22/7×h[(28)² + (7)² + 28×7)]


21560 = 1/3×22/7×h[ 784+49+196]


21560 = 1/3×22/7×h(1029)


21560 = 1/3×22/7× 1029H


H = 21560×3×7/22638


H = 452760/22638


H = 20 cm.


Slant height (L) = ✓(h)²+(R-r)²


= ✓(20)² + (28-7)²


= ✓400+441 = ✓841 = 29 cm


THEREFORE,


TSA of bucket = CSA of bucket + Area of Lower part of the bucket



= πL(R+r) + πr²



Putt the all values and solve.. you will get the TSA of bucket..



HOPE U GOT IT.... :-)

4.1

Radius of upper part of the bucket(R) = 28 cm


Radius of Lower part of the bucket(r)= 7 cm


Volume of the bucket = 1/3πh( R²+r²+Rr)


21560 = 1/3×22/7×h[(28)² + (7)² + 28×7)]


21560 = 1/3×22/7×h[ 784+49+196]


21560 = 1/3×22/7×h(1029)


21560 = 1/3×22/7× 1029H


H = 21560×3×7/22638


H = 452760/22638


H = 20 cm.


Slant height (L) = ✓(h)²+(R-r)²


= ✓(20)² + (28-7)²


= ✓400+441 = ✓841 = 29 cm


THEREFORE,


TSA of bucket = CSA of bucket + Area of Lower part of the bucket



= πL(R+r) + πr²



Putt the all values and solve.. you will get the TSA of bucket..

HOPE U GOT IT.... :-)

Plz mark as brainliest