A bucket of height 8 cm and made up of copper sheet in the form of frustum of a right circular cone with the radii of its lower and upper ends as 3 cm and 9 CM respectively calculate first the height of the cone of which the bucket is apart second the volume of water which can be filled in the buckets third the area of the copper sheet required to make the bucket
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Let h be the height, l the slant height and r1and r2 the radii of the circular bases of a frustum of a cone.
We have, h = 8 cm, r1 = 9 cm and r2 = 3 cm
(i) Let h1 be the height of the cone of which the bucket is part. Then

(ii) Volume of the water which can be filled in the bucket
= Volume of the frustum

(iii) Area of the copper sheet required to make the bucket
, where l is the slant height of the height of the frustrum

We have, h = 8 cm, r1 = 9 cm and r2 = 3 cm
(i) Let h1 be the height of the cone of which the bucket is part. Then

(ii) Volume of the water which can be filled in the bucket
= Volume of the frustum

(iii) Area of the copper sheet required to make the bucket
, where l is the slant height of the height of the frustrum

786007:
Can u plz make the diagram for that answer does not match with me
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