A bucket of height 8 cm and made up of copper sheet is in the form of frustum of a right circular cone
with radii of its lower and upper ends as 3 cm and 9 cm respectively. Calculate :
i) the height of right circular cone.
ii) the volume of water which can be filled in the bucket.
iii) the area of copper sheet required to make the bucket.
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Answer:
i) The height of the cone of which the bucket is a part of is 12 cm
ii) the volume of water which can be filled in the bucket is 312π cm³
iii) the area of metal sheet required to make the bucket is 129π cm²
Step-by-step explanation:
we have been given
h = 8 cm
r₁ = 9 cm
r₂ = 3 cm
Then slant height
L =
= √(8² + 6²)
= 10 cm
i) let h₁ be the height of the cone of which the bucket is a part of, so,
h₁ = hr₁/(r₁-r₂)
= 8 x 9/6
= 12 cm
ii) volume of the water which can be filled in the bucket
=
= 8π( 81 + 9 + 27)/3
= 8 x π x 117/3
= 312π cm³
iii) area of the metal sheet required to make the bucket = surface area
= πL(r₁ + r₂) + πr₂²
=π x 10 x 12 + 9π
= 129π cm²
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