A bucket open at the top, and made up of a metal sheet is in the form of a frustum of a cone. The depth of the bucket is 24 cm and the diameters of its upper and lower circular ends are 30 cm and 10 cm respectively. Find the cost of metal sheet used in it at the rate of Rs 10 per 100 cm 2 . [Use π = 3.14]
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Answer:
Step-by-step explanation:
Cost = area * rate
Area = LSA of frustum+ base area
= πl(r1 + r2) + πr2 square
Taking π r2 common...
= π r2 ( l (r1) + r2)
= 3.14 * 5 (26(15) + 5)
= 15.7(390+5)
= 6201.5cm square
Cost = area*rate
= 6201.5 * 10
= 62,015 rupees
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