Question

A bucket open at the top has top and bottom radii of circular ends as
40 cm and 20 cm respectively. Find the volume of the bucket if its depth
is 21 cm. Also find the area of the tin sheet required for making the
2
bucket.
​

Answer 1

Answer:

Volume of bucket =

3

1

π Height (R

top

2

+R

top

R

bottom

+R

bottom

2

) =

3

1

π×12(20

2

+20×10+10

2

)=8800cm

3

Slant height, l=

(20−10)

2

+12

2

=15.62cm

T.S.A =π(R

top

+R

bottom

)l+π(R

top

2

+R

bottom

2

)=3044.171cm

2

Cost=120×30.44171=Rs.3653

Step-by-step explanation:

Volume of bucket =

3

1

π Height (R

top

2

+R

top

R

bottom

+R

bottom

2

) =

3

1

π×12(20

2

+20×10+10

2

)=8800cm

3

Slant height, l=

(20−10)

2

+12

2

=15.62cm

T.S.A =π(R

top

+R

bottom

)l+π(R

top

2

+R

bottom

2

)=3044.171cm

2

Cost=120×30.44171=Rs.3653

Answer 2

FINAL ANSWER:-

sheet required for making 2 buckets $= 13451.42cm^{2}$

SOLUTION:-

tin  sheet required for making 1 bucket = $6725.21cm^{2}$ [ ≡ see the pic that i have attached ≡ ]

∴ sheet required for making 2 buckets = $2$ × $6425.71$

$= 13451.42cm^{2}$