Question

A bucket tied at the end of 1.6 m long string is whirled in a vertical circle, when the bucket is at the highest point, the minimum speed for the bucket not to spill water from it is (take g = 10 ms)





​

Answer 1

For the water not to spill out of bucket, the condition must be:

$\huge\boxed{\bold{\sf{mv^2=mg}}}}$

We have to find the minimum speed for the bucket not to spill water from it.

$\boxed{\bold{\sf{v^2=rg}}}$

Here,

• r = 1.6 m

• g = 10 m/s

Applying values to the equation:

$\sf{\implies v^2=1.6\times 10}$

$\sf{\implies v^2=16}$

$\sf{\implies v=\sqrt{16}}$

$\sf{\implies v=4 \ m/s}$

$\boxed{\bold{\sf{\therefore Minimum \ Speed=4 \ m/s}}}$