Question

A bucket tied at the end of 1.6m long string is whirled in a vertical circle with constant speed. what should be the minimum speed so that the water from the bucket does not spil when the bucket is at the highest position?

Answer 1

the minimum speed at the top is
$\sqrt{rg} \\ take \: r = 1.6m \\ g = 9.8\frac{m}{ {s}^{2} } \\ \sqrt{1.6 \times 9.8} = 3.95 \frac{m}{s}$

Answer 2

Explanation:

minimum speed =√gr

=√1.6*10 = √ 16

=4 m/sec