Question

A buffer pair (HA/A⁻) has a pKa of 7.4. At a blood pH of 7.4, the concentration of HA is
a. 1/100 that of [A⁻]
b. 1/10 that of [A⁻]
c. equal to that of [A⁻]
d. 10 times that of [A⁻]

Answer 1

use formula , pH = pKa + log₁₀[base]/[acid]
When reaction , HA ⇔H⁺ + A⁻
so, pH = pKa + log₁₀[A⁻]/[HA]

Given, pH = 7.4 and pKa = 7.4
7.4 = 7.4 + log₁₀ [A⁻]/[HA]
0 = log₁₀[A⁻]/[HA]
10⁰ = [A⁻]/[HA]
1 = [A⁻]/[HA]
Hence, concentration of A⁻ = concentration of HA

So, option (c) is correct.

Answer 2

Answer:

hey mate your answer is

Explanation:

C