a buffer solution contains 0.1M of acetic acid and 0.1M of sodium acetate(a 0.2M acetate buffer). What is the ph after 4 ml of a 0.05M HCl are added to 10 ml of the buffer (Ka=1.8*10-5)
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Answer:
Explanation:
So log(Salt/Acid)= 5.4–4.7447= 0.6553 . Therefore if the concentration of CH3-COONa is 4.522- times that of Acetic acid then the pH of the buffer will be =5.4.
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