Question

A bug decreases its Speed From 40 kmph
to 20 kmph in 10 min. finds its
acceleration.

Answer 1

Answer: -0.0092m/s

Explanation: u = 40km/h = 11.11m/s

                       v = 20km/h= 5.55m/s

                       t = 10 min = 60 sec

                       a = v-u/t

                            = $\frac{5.55-11.11}{600}$

                            = -0.0092m/s