Math, asked by angelashen1234, 1 month ago

A bug ran from -8 to 22. What distance did it cover? If the whole run took the bug 3 minutes, what was its average speed?

Answers

Answered by rohan3452
25

Answer:

This hasn’t been a great week for me, due to a host of mishaps. A bout with food poisoning, a fall down a flight of stairs, and some bug bites on my face that caused so much swelling that it was messing with my vision in my eye. As a result of that last one, my team made me leave the office and go to urgent care on my way to the airport today. Not good! This morning started out similarly poorly, with my next door neighbor at the hotel where I was staying blasting the TV at 4:45am. Okay, okay – I’m up! (PS – not staying at this hotel again now that I see how thin the walls are :P)

Step-by-step explanation:

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Answered by hareekshithasp3se3v
1

Answer:

Distance = 14m

Speed = 0.777 m/s

Step-by-step explanation:

Bug ran from -8 to 22. Hence the the initial and the final position is 0 and 14. -> Distance

The time taken by the bug to run this Distance = 3minutes = 180 seconds

Considering the unknown unit as meters,

The average speed = total Distance/ Total time

= 14m/180s = 0.777 m/s.

I hope it helps

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