A builder borrows rs. 2550 to be paid back with compound interest at the rate of 4% per annum by the end of 2 years in two equal yearly installments. How much will each installment be? ? Ans
Answers
Answer:
Given
P = Rs. 2550.
R = 4%
n = 2 years.
let installment = x
P= x/ (1+4/100) +x/(1+4/100)
=> 2550= x/1.04+ x/1.04+1.04
=> 2550= x/1.04 (1+1/1.04)
=> 2550= x/1.04 ×2.04 /1.04
=> 2550= 2.04x /1.0816
=> 2550 × 1.0816= 2.04x
=> 2758.08 / 2.04 =x
=> x = 1352
Equal installment would = Rs 1352
========================
@GauravSaxena01
Answer:
Each installment paid by the builder will be Rs. 28,125
Step-by-step explanation:
A= future amount of investment including interest
P= Initial amount of investment
r= annual rate of interest
n= number of times interest is compounded per year
t= number of years for which the money is invested or borrowed
P= Rs.2250
r=4%
n=1
t=2 years
A= P (1+r/n) ^(nt)
= 2250 ( 1+ 4/1) ^ (1x2)
= 2250 (1+4) ^ 2
= 2250 (5) ^ 2
= 2250 x 25
= Rs. 56,250
So the future amount of investment for 2 years is Rs. 56,250.
So, the amount of each installment will be = Rs. 56,250 / 2
= Rs. 28,125