Question

a builder of residential project has a vacant square land of side 21m.he want to make a temple in the shape of semi Circle

Answer 1

Answer:

42m

Step-by-step explanation:

Answer 2

The area of the square field $= 441m^{2}$  $(c)$

Area of the quadrants $=173.25m^{2}$ $(b)$

Area of the field for semicircular temple $=173.25m^{2}$ $(c)$

Area of the the unshaded region $= 346.5m^{2}$ $(b)$

Area of the shaded region $=94.5m^{2}$ $(d)$

Given:

Side of a vacant square land = 21 m

To find:

1. Area of the square
2. Area of two quadrants shown in the figure
3. Area of semicircular temple.
4. The area of the unshaded region
5. Area of the shaded region

Solution 1

We have been given a side of the square lets say $AB = 21 m$

Hence, area of the square field $= x^{2} = (side)^{2}$

                                                    $= (21)^{2}$

                                                    $=441 m^{2}$

Solution 2

In the given figure, we can see, 2 quadrants, that are meant to be made into a park.

Since, they are one fourth of a circle in shape,

Therefore, area of the quadrant = πR²/4

Total area of the park = 2 × πR²/4

                                     = πR²/2

Here,$R = \frac{21}{2} m$ ; that is the radius of a quadrant as well as half the side of the square field.

Hence, Area $=\frac{\frac{22}{7} (\frac{21}{2} )^{2}}{2}$

                     $=\frac{693}{4}$

                    $=173.25m^{2}$

Solution 3

In the figure, we can see, the area of temple is semi circular in shape, with the diameter of the semicircle being the side of square equal to 21 m.

Hence, the radius of the semicircle will be$= \frac{D}{2}=\frac{21}{2} m$

Now, the area of the semicircle will be = πR²/2

                                                                  = $\frac{ \frac{22}{7}(\frac{21}{2} )^{2} }{2}$

  Hence, area of the semicircle will be  $=173.25 m^{2}$

Solution 4

We know,

Area of region to be made into park$= 173.25 m^{2}$

Area of the region for temple = 173.25m^{2}

Hence, the area of the unshaded region will be $= (173.25+173.25)m^{2}$

                                                                                   $=346.5m^{2}$

Solution 5

Also, we know,

Total area of the field$=441m^{2}$

and, we calculated the unshaded region  $= 346.5m^{2}$

Hence, the area of the shaded region will be $= (441-346.5)m^{2}$

                                                                            $= 94.5m^{2}$

Final answer:

Hence,

1. The area of the square field $= 441m^{2}$  $(c)$
2. Area of the quadrants $=173.25m^{2}$ $(b)$
3. Area of the field for semicircular temple $=173.25m^{2}$ $(c)$
4. Area of the the unshaded region $= 346.5m^{2}$ $(b)$
5. Area of the shaded region $=94.5m^{2}$ $(d)$

Although your question is incomplete, you might be referring to the question below.

A builder of residential project have a vacant square land of side 21 m. He wants to make a temple in the shape of semi circle and a park in the shape of two quadrants of a circle as shown in the figure.