Question

A building casts a shadow that is 423meters long at the same time a person who is 4meter long casts a shadow 6meters long find the height of the building

Answer 1

$\large{\rm{Question:}}$

• A building casts a shadow that is 423meters long at the same time a person who is 4meter long casts a shadow 6meters long find the height of the building.

$\large{\rm{Given:}}$

• The length of shadow casted by building=423m
• The height of the person=4m
• The length of shadow casted by person=6m

$\large{\rm{To\:Find:}}$

• The height of the building

$\large{\rm{Solution:}}$

• $\sf{Let\:The\:height\:of\:building\:be\:h}$

$\rm{\implies \dfrac{Shadow\:of\: building}{shadow\:of\: person}=\dfrac{height\:of\: building}{height\:of\: person}}$

$\rm{\implies \dfrac{423}{6}=\dfrac{h}{4}}$

$\rm{\implies 6*h=423*4}$

$\rm{\implies \cancel{6}h=\cancel{1692}}$

$\rm\orange{\implies h=282m}$

Hence,

$\sf\purple{The\: height\:of\: building=282m}$

Answer 2

Given :

• 423 meter high building costs a shadow of 4 m.

We Need To Find :

• Height of building that casts a shadow of 4 m.

Step-by-step explanation :

Let height of building be x m.

Thus, our table look like,

________________________________

| Height of object (in metre ) = 423 | x |________________________________

| Length of shadow (in metre) = 6 | 4 |

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Now, as the height of object increases.

The length of its shadow also increases.

∴ They are in direct proportion :

➮ 423/6 = x/4

➮ 423/6 × 4 = x

➮ 423/3 × 2 = x

➮ 141 × 2 = x

➮ 282 = x.

Therefore, Height of building is 282 m.