Math, asked by eri1485, 7 months ago

a building in the form of a cylinder of radius 4m and height 6m.it is surmounted by a cone of height 3cm and has the same radius as that of the cylindrical portion.find the volume of the building and the outer surface area of the building(without the base).

Answers

Answered by dhimandeepakshi
5

Answer:

Volume of building = volume of cylinder + volume of cone

. . . . . . . . . . . . . . . . . = ( pie) r^3 h/3 + (pie) r^2*h

. . . . . . . . . . . . . . . . . = (pie) 64*6 /3 + (pie) 16*3

. . . . . . . . . . . . . . . . . = (pie) 128 + (pie) 48

. . . . . . . . . . . . . . . . . = 176(pie)

Outer surface area of building = surface area of cylinder + surface area of cone

. . . . . . . . . . . . . . . . . . . . . . . . . . = 2(pie)rh + (pie) r(r^2 + h^2)^1/2

. . . . . . . . . . . . . . . . . . . . . . . . . . = 2(pie)*12 + (pie) 4*5

. . . . . . . . . . . . . . . . . . . . . . . . . . = 24(pie) + 20(pie)

. . . . . . . . . . . . . . . . . . . . . . . . . . = 44(pie)

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