Question

A building worth Rs 133100 is constructed on land worth Rs 72900.after how many years Will the value Of both be same if the land appreciates at 10%p.a and building depreciates at 10%p.a​

Answer 1

ANSWER:---------

Explanation :

{Let the required time be n years. Then, 72900}

{x(1+10100)n =133100x(1−10100)}n}

{(1+10100)n =133100x(1-10100)}n

⇔ (1110)n×(109)n= 13310072900 

 ⇔(119)n= 1331729=(119)3  

⇔⇔ (1110)n×(109)n= 13310072900

  ⇔(119)n= 1331729=(119)3  ⇔n = 3.

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Answer 2

The value Of both be same if the land appreciates at 10%p.a and building depreciates at 10%p.a​ after 3 years

Step-by-step explanation:

Present value of building = 133100

The building depreciates at 10%p.a​

So, Value of Building after t years =$133100(1-0.1)^t$

Present value of land = 72900

The land appreciates at 10%p.a

So, Value of land after t years =$72900(1+0.1)^t$

So, $133100(1-0.1)^t=72900(1+0.1)^t$

t=3

Hence The value Of both be same if the land appreciates at 10%p.a and building depreciates at 10%p.a​ after 3 years

#Learn more:

The value of a flat worth rs.500000 is depreciating at the rate of 10% p.A. In how many years will its value be reduced to rs.364500?

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