Question

A bulb 100watt and 200volt is turned on for 2 min the charge passed is​

Answer 1

Answer:The power dissipated by an electric bulb is given as P = VI.

In this case, Power P = 100 W and Voltage V = 220 V.

So, current I is I = P/V = 100/220 = 0.45 A.

When the supplied voltage is 110 V, the power consumed will be P=VI = 110 * 0.45 = 50 W.

Hence, the power consumed when operated at 110 V is 50 W.

Explanation:

Answer 2

The power dissipated by an electric bulb is given as P = VI.

The power dissipated by an electric bulb is given as P = VI.In this case, Power P = 100 W and Voltage V = 220 V.

The power dissipated by an electric bulb is given as P = VI.In this case, Power P = 100 W and Voltage V = 220 V.So, current I is I = P/V = 100/220 = 0.45 A.

The power dissipated by an electric bulb is given as P = VI.In this case, Power P = 100 W and Voltage V = 220 V.So, current I is I = P/V = 100/220 = 0.45 A.When the supplied voltage is 110 V, the power consumed will be P=VI = 110 * 0.45 = 50 W.

The power dissipated by an electric bulb is given as P = VI.In this case, Power P = 100 W and Voltage V = 220 V.So, current I is I = P/V = 100/220 = 0.45 A.When the supplied voltage is 110 V, the power consumed will be P=VI = 110 * 0.45 = 50 W.Hence, the power consumed when operated at 110 V is 50 W.