A bulb and an ammeter are connected in series in a circuit .when the ciruit is connected to a 6 volt battery the reading of ammeter becomes 0.2A .calculate the resistance of bulb
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Explanation:
If v=6v
.. I= 0.2 A
R=?
V=I R
R = V/I
= 6/0.2
= 60/2
R = 30 ohm
Hope this answer will help you
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