Question

a bulb draws a current of 0.6 A from a cell of terminal potential difference 2V. find the resistance of the bulb​

Answer 1

Given:-

• Current (I) = 0.6 A
• Potential difference (V) = 2V

To find:-

• Resistance (R)

Formula to be used:-

$\longrightarrow$ $\underline\red{\boxed{\bf Resistance (R) = \dfrac{Voltage(V)}{Current(I)}}}$

Solution:-

$\implies$ $\bf Resistance = \dfrac{2}{0.6}$

$\implies$ $\bf Resistance = 3.33 Ω$

hence, the required value is 3.34 Ω (approx)