a bulb draws current 9A when connected to a 12V battery find 1) resistance of the bulb 2) charge flowing in 2s
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Answer:
- 1.33 Ω.
- 18 C.
Explanation:
Given: Electric current (I) = 9 A
& Voltage (V) = 12 V, Time taken (t) = 2 sec
To find: Resistance (R) & Charge (Q)
Solution: Using Ohm's law:
=> V = IR => 12 = 9(R)
=> R = 12/9 = 1.33 Ω
Now, charge (Q) = It
=> Q = 9(2) => 18 C
- Hence, the resistance of the bulb is 1.33 Ω and charge flowing in 2 sec is 18 C.
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