A Bulb emit light of wavelength, 400nm.
if the total energy emitted by bulb
is 3x10^-18 joules, the total number of photons
emitted by the bulb will be
Answers
Answered by
1
Answer: I hope it is helpful....
Explanation:
Power of the bulb = 100 watt = 100Js
−1
Energy of one photon is E=hν=hc/λ
where, h=6.626×10
−34
Js,c=3×10
8
ms
−1
Given λ=400nm=400×10
−9
m
By putting the values, we get
E=6.626×10
−34
×3×10
8
/(400×10
−9
)
E=4.969×10
−19
J
Number of photons emitted in 1 sec × energy of one photon = power
n×4.969×10
−19
=100
n=
4.969×10
−19
100
n=2.012×10
20
photons per sec
Answered by
3
Answer:
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