Question

A bulb has a resistance of 240 ohmsis connected to 12V battery the power consumption is

Answer 1

Answer:

Answer is 0.6W

Explanation:

P=V²/R

V=12v

R=240 putting tgese values

P=0.6W

hope it helps

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Answer 2

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A bulb has a resistance of 240 ohm is connected to 12V battery the power consumption is :

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From the Question,

• Resistance,R = 240 $\omega$
• Potential Difference V = 12 V

To finD

Power consumed by the battery

Electric Power

It is mathematically the product of current supplied and potential difference

$\longrightarrow \: \tt{P = I \times V}$

From Ohm's Law,

$\tt{I = \dfrac{V}{R} - - - - (1) }$

Using Relation (1),we write :

$\longrightarrow \: \boxed{ \boxed{\tt{P = \dfrac{ {V}^{2} }{R} }}}$

Putting the values,we get :

$\longmapsto \: \tt{P = \frac{ {12}^{2} }{240} } \\ \\ \longmapsto \: \tt{P = \frac{144}{240} } \\ \\ \longmapsto \: \boxed{\boxed{\tt{P = 0.6 \: watt}}}$

The power consumed by the 12V battery is 0.6 W