Question

a bulb is marked 220v and 40W. calculate the current flowing through the bulb and it's resistance​

Answer 1

The current flowing through the bulb and its resistance​ is 0.18 A and 1210 ohms respectively.

Explanation:

Given that,

Voltage of the bulb, V = 220 V

Power of the bulb, P = 40 W

Let I is the current through the bulb. The formula for the power in terms of voltage is given by :

$P=\dfrac{V^2}{R}$

R is the resistance of the bulb

$R=\dfrac{V^2}{P}$

$R=\dfrac{(220)^2}{40}$

R = 1210 ohms

The Ohm's law is used to find the current flowing through the bulb. It is given by :

$I=\dfrac{V}{R}$

$I=\dfrac{220}{1210}$

I = 0.18 A

So, the current flowing through the bulb and its resistance​ is 0.18 A and 1210 ohms respectively.

Learn more :

Topic : Electric current and power

https://brainly.in/question/12952568

Answer 2

Answer:

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