A bulb is placed at a depth of 2root 7m in water and floating opaque disc is placed over the bulb so that the bulb is not visible to the surface. the minimum diameter of the disc is a)42m b)6m c)2root7m d)12m
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The diameter of the disc is 12 cm.
Option (D) is correct.
Explanation:
We are given that:
h = 2√7 cm
Radius "R" = h / √μ^2 - 1
Radius "R" = 2√7 / √ (4/3)^2 - 1
Radius "R" = 2 √ 7 / (√7/3) = 6 cm
Diameter of disc = 2R = 2 x 6 = 12 cm
Thus the diameter of the disc is 12 cm.
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