A bulb is rated 200v-40w. What is its resistance? five such bulbs are lighted for 5 hrs. calculate the electric energy consumed.Find the cost if the rate is rupees 5 per kwh
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P=V^2/R
P=40W V=200 Volt
R=V^2/P
=(200×200)/40
=1000 ohm ans
I=V/R
=200/1000
=0.2 A
Energy =P×t ×5
=40×5×5=1000 kwh
Cost = 1000 × 5= Rs 5000
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P=40W V=200 Volt
R=V^2/P
=(200×200)/40
=1000 ohm ans
I=V/R
=200/1000
=0.2 A
Energy =P×t ×5
=40×5×5=1000 kwh
Cost = 1000 × 5= Rs 5000
Hope you liked the answer.
please mark it as brainliest.
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