a bulb is rated 3.0 v and 750ma calculate its (i) power (ii) its resistance and (iii) the energy consumed if bulb is lighted for 6 hours
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We know, Power=I^2R
P=750×3
P=2250 W
We know P=V/R
2250/3 =1/R
R= .0013 ohm
WE KNOW E=I^2RT
E= 3×3×.0013×6
E= .0702 N
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