A bulb is rated 5V, 100mA. Calculate its (i) power and (ii) resistance when it is connected to a 5V battery. Is there any change in its power and resistance if another bulb of same rating is inserted in series with it? Explain.
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Answer:
=50 Ω
Explanation:
V=5 volts i=100 mA=0.1 A
(a) : Power P=Vi=5×0.1=0.5 watt
(b) : Resistance R=
P
V
2
= 0.5
5
2
=50 Ω
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