Question

A bulb is rated 5V, 100mA. Calculate its (i) power and (ii) resistance when it is connected to a 5V battery. Is there any change in its power and resistance if another bulb of same rating is inserted in series with it? Explain.

Answer 1

Answer:

=50 Ω

Explanation:

V=5 volts i=100 mA=0.1 A

(a) : Power P=Vi=5×0.1=0.5 watt

(b) : Resistance R=

P

V

2

= 0.5

5

2

=50 Ω

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