Question

a bulb is rated at 200 volt and 40 watt what is Resistance? 5 such bulbs are lighted for 5 hours. calculate the electrical energy consumed. find the cost If the rate is Rs. 5.10 per kaha.

Answer 1

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This answer is verified✅✅

(a) . Calculation of Resistance

$p \: = \frac{ {v}^{2} }{r}$

Power , P = 40 watts
voltage, V = 200 volts
Resistance, R = ?


$40 \: = \frac{ {(200)}^{2} }{r}$
$40r = 40000$
$r \: = \frac{40000}{40}$
$r \: = 1000 \: ohms$

(b ) Calculation of Electrical Energy consumed.

E = P * t

Power, P = 40 watts
= 40/1000 kilowatt
= 0.04 kilowatt ......(1)
time ,t = 5 hours. .........(2)

so, Energy consumed by 1 bulb = 0.04*5
= 0.2 kWh
and , energy consumed by 5 bulbs = 0.2*5
= 1 kWh
Thus, the total electrical energy consumed is " 1 kWh or 1 units "

(c) Calculation of cost of Electrical Energy .

cost of 1 units of electricity = Rs.5.10


Hope you help........❤☺✌✊☺❤✌✊

Answer 2

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hope it will help you...