a bulb is rated at 200 volt to 240 watt what is its resistance 5 such balls are lighted for 5 hours calculate the electrical energy consumed find the cost if the rate is 5.10 per kwh
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the bulb is rated at 200v to generate power of 240 watt.
power= v²/r
240watt= 200×200/r
r=200×200/240= 166.67 ohm
total power of 5 bulbs = 240× 5=1200watt
convert it into kw = 1200/1000= 1.2 kw
(1.2×5) kw × h= 6 kwh
cost of 1kwh = 5.10 rupees
total cost = 6×5.10= 30.60 rupees
power= v²/r
240watt= 200×200/r
r=200×200/240= 166.67 ohm
total power of 5 bulbs = 240× 5=1200watt
convert it into kw = 1200/1000= 1.2 kw
(1.2×5) kw × h= 6 kwh
cost of 1kwh = 5.10 rupees
total cost = 6×5.10= 30.60 rupees
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