Physics, asked by Ashvaneet1512, 1 year ago

A bulb is rated at 200v 40w what us it resistance

Answers

Answered by Ramya2928
0

Explanation:

P = V²/R

40w=220*220/R

R=220*220/40

=1210.

Answered by MssShreya
1

Answer:

Here is your answer

Explanation:

V= 200VP=40WP=V^2/RR= V^2/P =200×200/40= 1000ohmTOT P=5×40= 200W =0.2k.

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