Question

A bulb is rated at 330V- 110W. What do you think is its resistance? Three such bulbs burn for 5hrs at a stretch. What is the energy consumed? Calculate the cost in rupees if the rate is 1.70 paise per unit? [ 990 ohms, Rs 28.05]

Answer 1

Answer:

Complete answer:

We have been given in the question that,

V=300VV=300V

P=110WP=110W

We know that for any given electrical appliance, the power is given by the formula,

Power=(Voltage)2ResistancePower=(Voltage)2Resistance

 

P=V2RP=V2R

Hence, the resistance will be,

R=V2PR=V2P

Now substituting the values of P and V in the formula we get resistance as,

R=(330)2110=108900110R=(330)2110=108900110

R=990ΩR=990Ω

Thus, the resistance of the bulb is 

990Ω990Ω

.

Now we will find the energy consumed by 3 bulbs burning at a stretch of 5 Hours,

We have been given that,

P=110WP=110W

Hope it helps you