Question

A bulb is rated at 330v-110w .What is its resistance?

Answer 1

$\bf{given} \div$

${\bf{power} }= 110w$

${ \bf{potential \: difference}} = 330v$

${ \bf{answer}} \: \div$

$\implies \: p = \frac{ {v}^{2} }{r}$

$\implies \: r = \frac{ {v}^{2} }{p}$

$\implies \: r = \frac{ {330}^{2} }{110}$

$\implies \: r = \frac{330 \times 330}{110}$

$\implies \: r = 990$

$\boxed{answer \: = 990 \: ohm}$