A bulb of (220 V, 60 W) is operated on 110 V supply then power developed in it is
(1) 15 W (2) 30 W (3) 65 W (4) 60 W
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Answered by
37
we know that P=V×V/R
therefore R=V×V/P
now R=220×220/60
R=2420/3
Now we know that P=V×V/R
NOW voltage is 110 V
P=110×110/2420/3=110×110×3/2420=15W.
Therefore correct answer is (1)15W
therefore R=V×V/P
now R=220×220/60
R=2420/3
Now we know that P=V×V/R
NOW voltage is 110 V
P=110×110/2420/3=110×110×3/2420=15W.
Therefore correct answer is (1)15W
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