A bulb of 220 V consume 1 unit in 25 hour Determine the power and resistance of bbulb.
Answers
Answered by
3
V=220V
T=25HRS
ENERGY CONSUMED = I²Rt= P*T
P= 1/25=1000/25
=40W
P= V*V/R
R= 220*220/40
= 1210 Ohm
Hope it helps..
T=25HRS
ENERGY CONSUMED = I²Rt= P*T
P= 1/25=1000/25
=40W
P= V*V/R
R= 220*220/40
= 1210 Ohm
Hope it helps..
Answered by
5
1 unit = 1kwh or 1000 Watthour
The bulb consumes 1 unit in 25 hours, that is, 1000WH in 25 hours.
Hence power = 1000/25 = 40 W
We know, V=IR & P=VI
I=V/R..applying this in power equation,
P = V^2/R
R= V^2/P = 220*220/40 =1210 ohm
Ans) 40W, 1210ohm
The bulb consumes 1 unit in 25 hours, that is, 1000WH in 25 hours.
Hence power = 1000/25 = 40 W
We know, V=IR & P=VI
I=V/R..applying this in power equation,
P = V^2/R
R= V^2/P = 220*220/40 =1210 ohm
Ans) 40W, 1210ohm
Similar questions