A bulb of 40W is connected across a source of 200V, then what will be the resistance of the bulb?
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Data : P = 40 W, V = 220 , V , R = ?
P=VI=V(VR)=V2R
R=V2P=(200V)240W=220×22040Ω=220×2202×20=Ω
=11×110Ω=1210Ω
The resistance of the bulb = 1210Ω
hope it helps you
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