Question

A bulb of 80 Watt is 6 hours daily. How many units (kWh) of electrical energy are consumed?​

Answer 1

Answer

Correct option is

B

0.36 units

Given :    t=6 hrs              

               P=0.06 kW

Thus energy consumed per day is:

E=Pt=0.06×6=0.36 kWh=0.36 units

Answer 2

$\huge\sf\fbox\red{Answer ࿐}$

Given : t = 6 hrs

P = 80 W

= 0.08 kW

Thus energy consumed per day is :

E = Pt

= 0.08 × 6 = 0.48 kWh

= 0.48 units