Question

A bulb of power 40 watt is designed to operate at 240v.calculate resistance of filament in the lamp

Answer 1

Answer:

P = V^2/R

R = 240×240/40

= 240×6=1440 ohm

Answer 2

Resistance of filament in the lamp is 1440 Ω

Explanation:

• Electric power of any appliance is defined as the amount of work done per unit time for which it is being operated or supply is on

                                           $Power = \frac{work done}{time taken}$

• Power have SI unit watt but bigger unit of power is kilo watt or even mega watt
• Power can be calculated as combination of voltage across the circuit and current flowing through the circuit

Given, Power = 40 watt

Voltage = 240 V

=> Power = voltage * current

=> P = V I

=> P = $\frac{V^{2} }{R}$

where R = resistance of the lamp

=> R = $\frac{240^{2} }{40}$

=> R = 1440 Ω

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