Physics, asked by risatmeem1482, 1 year ago

A bulb of resistance 400 ω connected to 200 v mains supply. calculate the magnitude of the current flowing through the bulb.

Answers

Answered by hyunxu
6
HOLA!!!

HERE WE GO

GIVEN

resistance = 400 ohms

voltage supply = 220v

current = ?

SOLUTION

According to ohm's law

V /I = R

I = V /R

I = 220/400

I = 0.55A

therefore the magnitude of current = 0.55

HOPE IT HELPS YOU:D
Answered by raktimachaurasiya
4
r=400ω
v=200v
i=  ...?
         
    
     v=ir
     
     i= v/r
   
     i= 200/400
    
     i=1/2
     i= o.5amp
 
    hope it helpfull

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