Question

A bulb of resistance 400 ohm is connected to 220V mains. calculate magnitude of the current

Answer 1

From Ohm's Law, it is know that,
V = I*R i.e. the voltage across the ends of a conductor equals the current through it times the resistance offered by the conductor,

or, 220V = I*400 ohm
or, I = 220/400 A
= 55/100 A
= 0.55 A, that is the current through the given wire.

Answer 2

Answer:

Current:

The amount of charge that travels through a specific reference point during a given time interval determines the magnitude of an electric current. Electric current is measured in amperes, with one ampere equaling one coulomb per second of charge flow. The amount of electrons flowing at any particular time is measured as current. As a result, each ampere represents a specific amount of electrons per second. This was a difficult number for me to remember, so I had to check it up. In other words, 1 amp is 6.242*10^18 electrons passing past per second.

Given:

A bulb of resistance 400 ohm is connected to 220V mains. calculate magnitude of the current

Find:

calculate magnitude of the current

Answer:

=> The ampere is the unit of (electrical) current (or milliampere, etc). The voltage of a resistor in the circuit can be used to measure or determine its magnitude. Then there's the math: A = E/R, where A is the current, E is the power loss from across resistor, and R is the resistor's Ohms value.

$R=400$ Ω

$V=220$ $V$

$I=?$

$V = IR$

$I=\frac{V}{R}$

$I=\frac{220 v}{400 ohm}$

$I = 5.5*10^{-1}$

$I = 0.55 A$

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