a bulb of resistance 400 ohms is connected to 220 v mains calculate the magnitude of current
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A bulb of resistance 400Ω is connected to 220V mains. Calculate the magnitude of current. I=V/R=220V/400Ω=0.55A
Answered by
3
Answer :-
- Magnitude of current is 0.55 A.
Explanation :-
Given :
- Resistance (R) = 400 Ω
- Potential difference (V) = 220 V
To find :
- Electric current (I)
Solution :
Using Ohm's law :
- V = IR
Substituting the values,
⇒ 220 = I × 400
⇒ I = 220/400
⇒ I = 0.55 A
- Magnitude of current is 0.55 A.
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