Question

A bulb rated 330 volt -110 watt.what do you think is its resistance ?find the energy consumed? calculate the east in rupee if the rate is 70 paise per unit .​

Answer 1

Answer:

Explanation:

Potential Difference = 330 V

Power = 110 watt

Now,

P = V^2/ R (Power = Potential Difference^2/Resistance)

Therefore, 110 = 330^2/R

=> R = 330^2/110

=> Resistance = 990 Ω

Understood?