a bulb rated 600W,240V . calculate its resistance when it is on. if the voltage dropsto 192V , what will be the power consumed and the current drawn
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Answer:
resistance R=96 ohm
power consumed P= 384 wats
current i= 2 amp
Explanation:
given p= 600 w , V = 240 V
we know P = Vxi , and V= ixR we also say i= V/R
we get P= Vx V/R
now putting values
600 = 240x240 / R
or resistance R = 240x240 / 600
=96 ohm
if voltage dropped to 192
then power P = VxV/R=192x192 / 96
P=384 wats
current i = V/R = 192/96 = 2 amp
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