A bulldozer attempts to drag a log weighing 500 N along the rough horizontal ground. The cable attached to the log makes an angle of 30° above the ground. The coefficient of static friction between the log and the ground is 0.50, and the coefficient of kinetic friction is 0.35. What minimum tension is required in the cable in order for the log to begin to slide?
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Given A bulldozer attempts to drag a log weighing 500 N along the rough horizontal ground. The cable attached to the log makes an angle of 30° above the ground. The coefficient of static friction between the log and the ground is 0.50, and the coefficient of kinetic friction is 0.35. What minimum tension is required in the cable in order for the log to begin to slide?
- Given weight of thee log = 500 N
- Cable makes an angle theta = 30 degree
- Coefficient of static friction between log and the ground μ = 0.50
- Coefficient of static friction μ = 0.35
- So the minimum tension in the cable required for the log to slide is
- T = μs w / cos theta + μs sin theta
- = 0.5 x 500 / cos 30 + 0.5 x sin 30
- = 250 / √3 / 2 + 0.5 / 2
- = 500 / √3 + 0.5 / 2
- = 500 / 1.732 + 0.5
- = 500 / 2.232
- T = 224 N
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