Question

A bullent train of mass 10g travelling horizontally with the velocity of 150m/s strikes a stationary wooden block and comes to rest in 0.03s. Calculate the distance of penetration of the bullet into the block. Also calculate the magnitude of the froce exerted by the wooden block on the bullet

Answer 1

Data: mass of the bullet (m) = 10 g = (10/1000) kg =0.01 kg Initial velocity (u) = 150 m/s Final velocity (v) = 0 m/s Time taken (t) = 0.03 sec i. Calculation of the distance of penetrationof the bullet into the block: Calculation of the distance of penetrationof the bullet into the block = Displacement Displacement = average velocity × time Displacement = [(u + v) / 2] × time Displacement = [(150 + 0) / 2] × 0.03 Displacement = 2.25 m ii. Calculation of the magnitude of the force exerted by the wooden block on the bullet: the magnitude of the force exerted by the wooden block on the bullet = Retarding force Retarding force = mass × reatardation Retarding force = mass ×[ (Intitial velocity - Final velocity) / t ] Retarding force = 0.01 ×[ (150 - 0) / 0.03 ] N Retarding force = [150/3] N Retarding force =50 Newton.

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