Question

a bullet as a mass of 0.05kg with an velocity of 80m/s and it enters a wooden block its resistive force act on the bullet and its distance is 0.40m.what force is required to stop the bullet by the wooden block

Answer 1

According to Newton's second law of motion

Force = mass × velocity / time

here in , final velocity = 0

mass = 0.05kg

velocity = 80m/s

distance = 0.40m

so F = 0.05 × v^2 / 2s ( a = v^2 – u^2/ 2s )

= 0.05 × 6400 / 0.80

= 5 × 6400 / 80

= 5 × 80

= 400N.

Hope it helps!

Answer 2

Explanation: as W=DK=F×S=1/2mv^2

So F=1/2×0.05×80×80÷0.4= 400N