A bullet blasts from the barrel of a gun upward in the vertical direction with an initial speed of 700 m/s. Find the maximum altitude reached by this bullet and the time needed to reach it
Answers
Answered by
2
HEY MATE HERE IS YOUR ANSWER
v= Vi - 9.81 t
at top v=0
So,
t= 700/9.81=71.4 sec
Now there are two ways to proceed one way:
h=Vit-4.9^2
h=700(71.4)-4.9(71.4)^2
h= 25000m
ANOTHER way
Average speed up = (700+0)/2=350m/s
h=350*71.4= 25000m
THANKS HOPE IT WILL HELP YOU
BE BRAINLY
MARK ME AS BRAINLIEST
v= Vi - 9.81 t
at top v=0
So,
t= 700/9.81=71.4 sec
Now there are two ways to proceed one way:
h=Vit-4.9^2
h=700(71.4)-4.9(71.4)^2
h= 25000m
ANOTHER way
Average speed up = (700+0)/2=350m/s
h=350*71.4= 25000m
THANKS HOPE IT WILL HELP YOU
BE BRAINLY
MARK ME AS BRAINLIEST
samsij7samsij:
* ehat does this stands for
Answered by
2
hello friend your answer .......
v=vi-9.81t
top v=0
then,
t=700/9.81=71.4seconds
h=vit-4.9²
h=700(71.4)-4.9(71.4)
h=25000m
v=vi-9.81t
top v=0
then,
t=700/9.81=71.4seconds
h=vit-4.9²
h=700(71.4)-4.9(71.4)
h=25000m
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