A bullet can merely penetrate 1 wooden block. If its velocity is raised from
12m/s to 32m/s, how many similar blocks it can penetrate?
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Let the uniform deceleration of bullet be a as final velocity
v=0,u=150,t=0.03 s
⇒v=u−−at⇒0=150−0.03
⇒a=0.03150=5000 m/sec2
& S=2av2−u2=−2(5000)−(150)2=100225=2.25 m
& F=ma=10×10−3×5×103
F=50 N
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Explanation:
answer is f=50n hope it's helps you
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