A bullet comes out of the barrel of gun of
length 2 m with a speed of 800 m/s. The
average acceleration of the bullet is
(a) 160 m/s2 (b) 60 km/s2
(c) 100 km/s2 (d) 160 km/s2
Answers
Answered by
14
‼️ HôLÅ ‼️
v² = u² + 2as
v² = 2as ..... [since , u = 0]
a = 800 x 800/2 x 2
a = 400 x 400
a = 160000m/s²
a = 160 km/s²
Have a nice day ! ❤️☺️
Answered by
1
Answer:
The average acceleration of the bullet is equal to 160 km/s².
Therefore, the option (d) is correct.
Explanation:
We have given, the speed of the bullet, v = 800m/s
Initially the bullet was at rest, so the initial speed of the bullet, u=0
The distanced travelled by bullet, S = 2m
We can use the 3rd equation of motion to find the average acceleration of the bullet.
v² = u² + 2aS
(800)² = (0)² + 2a(2)
640000 = 4a
a = 160000 m/s²
a = 160 Km/s² [∵ 1 Km = 1000m]
Therefore, the average acceleration of the bullet will be equal to 160 Km/s².
Similar questions