Question

A bullet emerges from a barrel of length 1.2 m with a speed of 640m/s. Assuming constant acceleration, the approximate time that it spends in
the barrel after the gun is fired.​

Answer 1

Answer:

t=3/1600

we can see that the distance is very small and does acceleration is increased very small which is approximately 0m/s^2

Answer 2

Answer:

(I). The acceleration is $1.7\times10^{5}\ m/s^2$

(II). The time interval is 3.76 ms.

Explanation:

Given that,

length = 1.2 m

Speed = 640 m/s

We need to calculate the acceleration

Using equation of motion

$v^2=u^2+2as$

$a=\dfrac{v^2-u^2}{2s}$

Put the value into the formula

$a=\dfrac{640^2-0}{2\times1.2}$

$a=170666.6\ m/s^2$

$a=1.7\times10^{5}\ m/s^2$

We need to calculate the time interval

Using equation of motion

$v = u+at$

$t=\dfrac{v-u}{a}$

Put the value into the formula

$t=\dfrac{640-0}{1.7\times10^{5}}$

$t=0.00376\ sec$

$t=3.76\ ms$

Hence, (I). The acceleration is $1.7\times10^{5}\ m/s^2$

(II). The time interval is 3.76 ms.