Question

A bullet entered into a wooden block with a speed of 200m per second after traveling 400 cm it stopped calculate the retardation of the bullet​

Answer 1

★★Question ;-

✓✓A bullet entered into a wooden block with a speed of 200m per second after traveling 400 cm it stopped calculate the retardation of the bullet.

★★Given;-

• Speed of bullet $(u)=200m/s$

• Final velocity $(v)=0m/s$

• Distance travelled before stoping$=400cm$

★★To find;-

• Retardation of bullet

★★Answer:-

Using 3rd equation of motion,

$\boxed{\boxed{{⇢{v}^{2}={u}^{2}+2as}}}$

$\dashrightarrow{(0)}^{2}=({200})^{2}+2×a×\frac{400}{100}$

$\dashrightarrow40000=-2×a×4$

$⇢=\frac{-40000}{8}$

$⇢{a}=-5000m/{s}^{2}$

So,final result is,

$\boxed{\boxed{{∴Retardation=-5000m/{s}^{2}}}}$✓✓

Answer 2

Aɴꜱᴡᴇʀ

$\large \red{\sf{\leadsto \: Retardation \: is \: - \: 5000 \: ms^{-2}}}$

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Gɪᴠᴇɴ

• Initial velocity (u) = 200 m/s
• Final velocity (v) = 0 m/s
• Distance travelled into wooden block before it stop (s) = 400 cm = 4 m

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ᴛᴏ ꜰɪɴᴅ

Retardation of the bullet

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Sᴛᴇᴘꜱ

With the use of 3rd equation of motion :

$\begin{lgathered}\dashrightarrow \boxed{\tt{v^2 \: - \: u^2 \: = \: 2as}} \\ \\ \dashrightarrow \tt{0^2 \: - \: 200^2 \: = \: 2 \: \times \: 4 \: \times \: a} \\ \\ \dashrightarrow \tt{-40000 \: = \: 8a} \\ \\ \dashrightarrow \tt{a \: = \: \dfrac{-40000}{8}} \\ \\ \dashrightarrow \tt{a \: = \: \dfrac{-40000}{8}} \\ \\ \dashrightarrow \tt{a \: = \: -5000} \\ \\ \pink{\sf{\leadsto \: Retardation \: is \: - \: 5000 \: ms^{-2}}}\end{lgathered}$

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$\huge{\mathfrak{\purple{hope\; it \;helps}}}$